Question

Calculati:
(radical din 0.(3)+2radical din 3supra3)·radical din 3+(radical din 0,(2)+4supra3 radical din 2)·radical din2

Answer 1

( √0,(3) + 2√3/3) ·√3 + ( √0,(2) + 4/3·√2 )· √2 =
= ( √3√9  +2√3/3)·√3 + ( √2/9 + 4√2/3)·√2=
= ( √3 ·√3) / √9 + (2√3 · √3) / 3 + ( √2·√2) /9 + ( 4√2·√2) / 3 =
= √9 / √9 + 2√9 /3 + √4 / 9 + 4√4 / 3 =
= 3 / 3 + 2·3 / 3 + 2 / 9 + 4·2 /3 =
= 1 + 6/3 + 2/9 + 6/3 =
= 1 + 2 + 2/9 + 2 =
= 5 + 2/9=
= ( 5·9 + 2)/ 9 =
= 47/9