Question

Calculaţi raza cercului inscris in triunghiul ABC cu AB=AC=5,si BC=8.

Answer 1

$r= \frac{Sabc}{p}$
$p= \frac{AB+AC+BC}{2} = \frac{5+5+8}{2} =9$
$Sabc \sqrt{p(p-AB)(p-BC)(p-AC)} = \sqrt{9*(9-5)(9-5)(9-8)} =12$
$=|\ \textgreater \ r= \frac{12}{9} = \frac{4}{3}$