Question

calculati , respectand oridinea operatilor si a parantezelor : 
a) [( 7/36-11/72-5/24) : 0,(6) + 0,75 ] · 0,5 + 3/4 ! 

Answer 1

[tex][( \frac{7}{36} - \frac{11}{72} - \frac{5}{24}):0,(6)+0,75]*0,5+ \frac{3}{4}= \\ \\ Aducem~la~acelasi~numitor~in~paranteza~rotunda: \\ \\ {[(\frac{14}{72}- \frac{11}{72}- \frac{15}{72}): \frac{6}{9}+ \frac{75}{100}]}* \frac{5}{10}+ \frac{3}{4}= \\ \\ (-\frac{12}{72}* \frac{3}{2}+ \frac{3}{4})* \frac{1}{2}+ \frac{3}{4}= \\ \\ (-\frac{6}{24}+\frac{3}{4})* \frac{1}{2}+ \frac{3}{4}= \\ \\ (-\frac{1}{4}+ \frac{3}{4})* \frac{1}{2}+ \frac{3}{4}= \\ \\ \frac{2}{4}* \frac{1}{2}+ \frac{3}{4}=[/tex]
[tex] \frac{1}{4}+ \frac{3}{4}= \\ \\ \frac{4}{4}=1[/tex]