Question

calculati suma nr.pare si suma nr.impare mai mari decat 2437 si mai mici decat 3712

Answer 1

$2437+2438+2439+...+3711+3712$
$=(1+2+3+...+3712)-(1+2+3+...+2436)$
$= \frac{3712*3713}{2}- \frac{2436*2437}{2}$
$=6891328-2968266$
$=3923062$