Question

Calculati :
$a= \sqrt{(2 \sqrt{3} } -3 \sqrt{2} )^2$

si

$b= \frac{9}{2 \sqrt{3} } - \sqrt{3}$

Answer 1

$a=\sqrt{(2\sqrt3-3\sqrt2)^2} = |2\sqrt3-3\sqrt2| = -2\sqrt3+3\sqrt2$

b)

$... = \dfrac{9\sqrt3}{2\cdot3}-\sqrt3=\dfrac{3\sqrt3}{2} -\dfrac{\sqrt3}{1} =\dfrac{3\sqrt3 -2\sqrt3}{2} =\dfrac{\sqrt3}{2}$