Question

calculati un intreg si 1 supra 2 plus 2 intregi si 1 supra 3 minus 3

Answer 1

$1 \dfrac{1}{2} + 2 \dfrac{1}{3} - 3 = \\ \\ \\ \dfrac{3}{2}^{ \times 3} + \dfrac{7}{3}^{ \times 2} - \dfrac{3}{1}^{ \times 6} = \\ \\ \\ \dfrac{9}{6} + \dfrac{14}{6} - \dfrac{18}{6} = \\ \\ \\ \dfrac{23}{6} - \dfrac{18}{6} = \dfrac{5}{6}$

Answer 2

Mult succes în continuare!