Question

calculati va rog urgent

Answer 1

3√3-6<0
I3√3-6I = -3√3+6
√3-3 <0
I√3-3I = -√3+3

[I3√3-6I +√(√3-2)²]/I√3-3I-1 =
=(-3√3+6 +√3-2)/(3-√3-1) =
=(4-2√3)/(2-√3) =
=2(2-√3)/(2-√3) =
=2