Question

Calculati valoarea numarului real
N=( √2+√3+1)la patrat -2(√6+√3+√2). Rezolvati ecuatia N supra 2 ori x= x la patrat+2

Answer 1

N=(√2+√3+1)²-2(√6+√3+√2)
  =2+√6+√2+√6+3+√3+√2+√3+1-2(√6+√3+√2)
  =6+2√6+2√2+2√3-2√6-2√3-2√2
N=6
(N/2)·x=x²+2
6x/2=x²+2
3x=x²+2
x²-3x+2=0
Δ=9-8=1
xunu=3+1/6=4/6 simplificam
xunu=2/3
xdoi=3-1/6=2/6 simplificam
xdoi=1/3