Question

Calculati volumul ocupat in condiții normale de temperatura si presiune de :

a. 14,2 kg Cl2
b. 15,055 * 10 la puterea 23 molecule Cl2.

Answer 1

Rezolv in 2 metode:

Metoda I:

a. MCl2=71kg/kmol

n=m/M=14,2/71=0,2 kmoli Cl2

n=V/Vm==>V=n*Vm=0,2*22,4=4,48m3=4480L Cl2

b. 1mol Cl2..............................2NA=12.044*10^23 molecule
    x=1,25 moli....................................15,055*10^23 molecule

n=V/Vm==>V=n*Vm=1,25*22,4=28 L Cl2

Metoda II:
a

a. T=273K
p=1
R=0.082

MCl2=71kg/kmol

n=m/M=14,2/71=0,2 kmoli Cl2

pV=nRT==>V=nRT/p=0,2*0,082*273/1=4,4772m3=4477,2L Cl2

b. Stim nr de moli de la punctul b => 1,25 moli Cl2

pV=nRT==>V=nRT/p=1,25*0,082*273/1=27,9825L Cl2