Question

calculatii urmatoarea ecuatie​

Answer 1

$[\frac{(1-2i)(3i-1)}{5}] ^4 \\\frac{(1-2i)(3i-1)}{5}=(3i-1-6i^2+2i)/5=(5i+5)/5=(i+1)\\(i+1)^4=(i+1)^2 (i+1)^2=(i^2+2i+1)^2=(2i)^2=-4$