Question

Calculează: 1+2+3+...+73

Answer 1

 

[tex] \displaystyle\\ 1+2+3+...+73 =\frac{73(73+1)}{2}=\frac{73 \times 74}{2}=73 \times 37=\boxed{\bf 2701} [/tex]

Answer 2

Suma lui Gauss

1 + 2 + 3 + ........ + 73 =

formula este :  S = n( n + 1 ) : 2

n = ultimul numar , 73 .

S = 73( 73 + 1 ) : 2

S = 73 × 74 : 2

S = 5402 : 2

Suma = 2701

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