calculeaza 11+22+33+...+99=?
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10
11+22+33+...+99=
11(1+2+3+4+.....+9)=
11*[9(1+9)/2]=
11*(9*10/2)=
11*45=495
11(1+2+3+4+.....+9)=
11*[9(1+9)/2]=
11*(9*10/2)=
11*45=495
dianapetrov:
multumesc
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0
11+22+33+...+99=
=11*1+11*2+11*3+...+11*9=
=11(1+2+3+...+9)=


=11*1+11*2+11*3+...+11*9=
=11(1+2+3+...+9)=
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