Question

Calculeaza: a) √16:√2+√18; b) √3*√15-2√75; c) √120:√10-√15:√5;​

Answer 1

Răspuns:

$\sqrt{16} = 4 \\ \sqrt{2 } = \sqrt{2} \\ \sqrt{18} = 3 \sqrt{2} \\ \sqrt{16} \div \sqrt{2} + \sqrt{18} = 2 \sqrt{2} + 3 \sqrt{2} = 5 \sqrt{2} \\ \\ \\ \sqrt{3 } \times \sqrt{15} - 2 \sqrt{75} = 3 \sqrt{5} - 5 \sqrt{3} \\ \\ \\ \sqrt{120 } \div \sqrt{10} - \sqrt{15} \div \sqrt{5} = 2 \sqrt{3} - \sqrt{3} = \sqrt{3}$