Question

calculeaza a la puterea b si b la puterea a stiind ca a=[(12la putetea a 2-5la puterea a 3)×2la puterea a 3-11la putetea a 2+1la puterea a 5]÷2la putetea a 2 si b={[(17la putetea a 2+13la putetea a 2-21la puterea a 2)×2la putetea 1+2la putetea 1]÷2}÷3 la puterea a 2
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Answer 1

Exercițiul 1

a = [(12²-5³)×2³-11²+1^5]÷2²

a = [(144-125)×2³-11²+1^5]÷2²

a = (19×2³-11²+1^5)÷2²

a = (19×8-121+1)÷2²

a = (152-121+1)÷2²

a = (31+1)÷2²

a = 32÷2²

a = 32÷4

a = 8

b = {[(17²+13²-21²)×2¹+2¹]÷2}÷3²

b = {[(289+169-441)×2¹+2¹]÷2}÷3²

b = {[(458-441)×2¹+2¹]÷2}÷3²

b = [(17×2+2)÷2]÷3²

b = [(34+2)÷2]÷3²

b = (36÷2)÷3²

b = 18÷3²

b = 18÷9

b = 2

a^b => 8^2 = 8 × 8 = 64

b^a => 2^8 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 4 × 4 × 4 × 4 = 16 × 16 = 256