Question

Calculează compozita procentuala prin masa atomica si raportul de masa a HCl, SO3, H3PO4, HCa, CaCl. PLS REPEDE

Answer 1

In primul rand ai scris formulele gresit 
pentru raport de masa 
HCl
H:Cl=1x1: 1x35.5
=1:35.5
SO3
S:O=1X32:3X16 SE SIMPLIFICA PRIN 16
=2: 3
H3PO4
H:P:O=3X1:1X31: 4X16
=3:31:64
H2Ca
H:Ca= 2X1: 1X40 SE simplifica prin 2
=1:20
CaCl2
Ca:Cl=1x40: 2x35,5 se simplifica prin 2
=20:35.5
Compozitie 
M=1AH+1XACl
=1x1+1x35,5
=36,5
36,5......1...........35.5
100........y............z
se determina y =.2.74.
z=97.26
S03
M=1XAS+3XAO
=1X32+3X16
=32+48
=80G/MOL
80............32..................48
100...........Y...................Z
SE DETERMINA Y=40
Z=60
H3PO4
M=3XAH+1XAP+4XAO
=3X1+1X31+4X16
=3+31+64
=98G/MOL
98...........3..............31..........64
100...........Y................Z.........T
Y=3.06
Z=31.63
T=65.30
H2Ca
M=2XAH+1XACa
=2X1+1X40
=2+40
=42G/MOL
42...............2.............................40
100.............Y..............................Y
Y=4.76
Y=95.23
CaCl2
M=1XACa+2xACl
=1x40+2x35,5
=40+71
=111g/mol
111....................40...............................71
100.....................y....................................z
y=36.03
z=63.96
am folosit x pentru inmultire