Question

calculeaza .cum se calculeaza

Answer 1

[tex]X = (2^0+8^{21}:16^{15}+6*27^{10}:81^7-61)^3 \\ X = [1+(2^3)^{21}:(2^4)^{15}+6*(3^3)^{10}:(3^4)^7-61]^3 \\ X = (1+2^{63}:2^{60}+6*3^{30}:3^{28}-61)^3 \\ X = (1+2^3+6*3^2-61)^3 \\ X = (1+8+54-61)^3 \\ X = 2^3 = 8[/tex]
[tex]Y = (2^{25}:2^{5^2}*5^3)^{42} \\ Y = (2^{25}:2^{25}*5^3)^{42} = (1*5^3)^{42} = (5^3)^{42}=\ \textgreater \ Y = 5^{126[/tex]

Sfat: Regulile de calcul cu puteri:
[tex]a^m*a^n=a^{m+n} \\ a^m:a^n=a^{m-n} \\ (a^m)^n=a^{m*n} \\ (a*b)^m=a^m * b^m[/tex]