Question

Calculeaza folosind factorul comun: a) (2^20+2^19-2^17):11; b) (3^25-3^23+3^22):25

Answer 1

Răspuns:

$(2 {}^{20} + 2 {}^{19} - 2 {}^{17} ) \div 11 = (2 {}^{3} + {2}^{2} - 1) {2}^{17} \div 11 = (8 + 4 - 1) \times {2}^{17} \div 11 = 11 \times {2}^{17} \div 11 = 1 \times {2}^{17} = 2 {}^{17}$