Question

Calculează,folosind factorul comun: a) (4+8+12+...+2012)÷(2+4+6+...+1006)= b) (12+24+36+...+444)÷(6+12+18+...+222)= Ajutați-mă va rog repede

Answer 1

Răspuns:

Explicație pas cu pas:

a) (4+8+12+...+2012)÷(2+4+6+...+1006)

= 2(2+4+6+...+1006) : (2+4+6+...+1006) = 2

_____________

b) (12+24+36+...+444)÷(6+12+18+...+222)=

2(6+12+18+...+222) : (6+12+18+...+222) = 2

Answer 2

a) (4+8+12+....+2012):(2+4+6+...+1006)=

=4(1+2+3+.....+503):2(1+2+3+.....+503)=2

b) (12+24+36+....+444):(6+12+18+...+222)=

=12(1+2+3+....+37):6(1+2+3+......+37)=2