calculeaza în ambele moduri: 2×(3+2)
3×(4+5)
4×(2+8)
6×(3+5)
7×(2+1)
2×(3-2)
3×(7-3)
5×(6-4)
8×(5-3)
9×(9-6)
Va rog
Răspunsuri la întrebare
Explicație:
2×(3+2)=2×5=10
2×3+2×2=6+4=10
3×(4+5)=3×9=27
3×4+3×5=12+15=27
4×(2+8)=4×10=40
4×2+4×8=8+32=40
6×(3+5)=6×8=48
6×3+6×5=18+30=48
7×(2+1)=7×3=21
7×2+7×1=14+7=21
2×(3-2)=2×1=2
2×3-2×2=6-4=2
3×(7-3)=3×4=12
3×7-3×3=21-9=12
5×(6-4)=5×2=10
5×6-5×4=30-20=10
8×(5-3)=8×2=16
8×5-8×3=40-24=16
9×(9-6)=9×3=27
9×9-9×6=81-54=27
Primul mod :
2 × ( 3 + 2 ) =
2 × 5 = 10
Al doilea mod :
2 × ( 3 + 2 ) =
2 × 3 + 2 × 2 =
6 + 4 = 10
Primul mod :
3 × ( 4 + 5 ) =
3 × 9 = 27
Al doilea mod :
3 × ( 4 + 5 ) =
3 × 4 + 3 × 5 =
12 + 15 = 27
Primul mod :
4 × ( 2 + 8 ) =
4 × 10 = 40
Al doilea mod :
4 × ( 2 + 8 ) =
4 × 2 + 4 × 8 =
8 + 32 = 40
Primul mod :
6 × ( 3 + 5 ) =
6 × 8 = 48
Al doilea mod :
6 × ( 3 + 5 ) =
6 × 3 + 6 × 5 =
18 + 30 = 48
Primul mod :
7 × ( 2 + 1 ) =
7 × 3 = 21
Al doilea mod :
7 × ( 2 + 1 ) =
7 × 2 + 7 × 1 =
14 + 7 = 21
Primul mod :
2 × ( 3 - 2 ) =
2 × 1 = 2
Al doilea mod :
2 × ( 3 - 2 ) =
2 × 3 - 2 × 2 =
6 - 4 = 2
Primul mod :
3 × ( 7 - 3 ) =
3 × 4 = 12
Al doilea mod :
3 × ( 7 - 3 ) =
3 × 7 - 3 × 3 =
21 - 9 = 12
Primul mod :
5 × ( 6 - 4 ) =
5 × 2 = 10
Al doilea mod :
5 × ( 6 - 4 ) =
5 × 6 - 5 × 4 =
30 - 20 = 10
Primul mod :
8 × ( 5 - 3 ) =
8 × 2 = 16
Al doilea mod :
8 × ( 5 - 3) =
8 × 5 - 8 × 3 =
40 - 24 = 16
Primul mod :
9 × ( 9 - 6 ) =
9 × 3 = 27
Al doilea mod :
9 × ( 9 - 6 ) =
9 × 9 - 9 × 6 =
81 - 54 = 27