Question

calculează in doua moduri: 5×(134+537)= 21×(98+345)= 3×(790-99)= 56×(76+98)= 4×(728-179)= 43×(157+473)=​

Answer 1

Răspuns:

Explicație pas cu pas:

Mod 1

5 × (134 + 537) = 5 × 671 = 3 355

Mod 2

5 × (134 + 537) = 5 × 134 + 5 × 537

= 670 + 2 685 = 3 355

Mod 1

21 × (98 + 345) = 21 × 443 = 9 303

Mod 2

21 × (98 + 345) = 21 × 98 + 21 × 345

= 2 058 + 7 245 = 9 303

Mod 1

3 × (790 - 99) = 3 × 691 = 2 073

Mod 2

3 × (790 - 99) = 3 × 790 - 3 × 99

= 2 370 - 297 = 2 073

Mod 1

56 × (76 + 98) = 56 × 174 = 9 744

Mod 2

56 × (76 + 98) = 56 × 76 + 56 × 98

= 4 256 + 5 488 = 9 744

Mod 1

4 × (728 - 179) = 4 × 549 = 2 196

Mod 2

4 × (728 - 179) = 4 × 728 - 4 × 179

= 2 912 - 716 = 2 196

Mod 1

43 × (157 + 473) = 43 × 630 = 27 090

Mod 2

43 × (157 + 473) = 43 × 157 + 43 × 473

= 6 751 + 20 339 = 27 090