Question

Calculează în două moduri:
A = –2 – (4 – 6); B = –3 – (–2 – 5) – (8 – 10);
C = –25 – (–12 + 8) – (–5 + 11); D = 14 – (7 – 3 + 14) – (–10 + 5).

Answer 1

Răspuns:

Explicație pas cu pas:

A = –2 – (4 – 6) =  - 2 - ( - 2 ) = - 2 + 2 = 0 → primul mod

A = - 2 - 4 + 6 = - 6 + 6 = 0 → al doilea mod

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B = –3  – (–2 – 5) – (8 – 10) = - 3 - ( - 7 ) - ( - 2 ) = - 3 + 7 + 2 = 4 + 2 = 6

B = - 3 + 2 + 5 - 8 + 10 = - 1 - 3 + 10 = - 4 + 10 = 6 → al doilea mod

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C = –25 – (–12 + 8) – (–5 + 11) = - 25 - ( - 4 ) - ( + 6 )

C = - 25 + 4 - 6 = - 21 - 6 = - 27 → primul mod

C = - 25 + 12 - 8 + 5 - 11 = - 13 - 3 - 11 = - 16 - 11 = - 27 → al doilea mod

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D = 14 – (7 – 3 + 14) – (–10 + 5) = 14 - ( 4 + 14 ) - ( - 5 )

D = 14 - 18 + 5 = - 4 + 5 = 1 → primul mod

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D = 14 - 7 + 3 - 14 + 10 - 5

D = 7 - 11 + 5

D = - 4 + 5

D = 1 =>  al doilea mod