Question

Calculeaza in doua moduri fiecare in parte ;
a) (6+7+4)x3
b) (36-16-8):4
c) (4+8+3)x4

Answer 1

a)(6+7+4)x3=
17x3=51
6x3+7x3+4x3=
18+21+12=51

b)(36-16-8):4=
12:4=3

36:4-16:4-8:4=
9-4-2=3

c)(4+8+3)x4=
15x4=60

4x4+8x4+3x4=
16+32+12=60

Answer 2

a) (6+7+4)x3= 17 x 3 = 51
    (6+7+4)x3= (3x4)+ (3x7) + (3x6)= 12+21+18 = 51

b)(36-16-8):4= 12/4= 3
   (36-16-8):4= (36/4)- (16/4) - (8/4) = 9-4-2= 5-2 = 3


c) (4+8+3)x4 =15 x 4 = 60
   (4+8+3)x4 = (4x4) + (4x8)  + (4x3) = 16+32+12= 60