Question

O hidrocarbura are densitatea in raport cu aerul 1,038 si are 80% C. Determinati formula moleculara.

Answer 1

daer=28,9

dgaz=M/Mgaz=>M=1,038*28,9=30g/mol

C=80/12=6,666  ||:6,666=>1 atom C

H=20/1=20 ||:6,666 => 3 atomi H

Formu;a bruta =>(CH3)n

Formula moleculara => 12n+3n=30 => 15n=30 =>n=2  => C2H6 - etanul