Calculează masa a al 35 moli Cabry b) 2 kmoli CaO; c) 15 mmoli NaNO₂. Calculează numarul de molecule dinc all 272 g H-Sp bl 10,2 kg NH d) 100 mL acetonă CH₂O (p=0,8 g/mL)
Răspunsuri la întrebare
Răspuns:
Explicație:
a.
35moli CaBr2
m= n . M
m= 40 + 2. 80= 200-----> 200g/moli
m= 2moli . 200g/moli= 400g CaBr2
b.
2kmoli CaO----> 2000moli
M= 40 + 16=56-----> 56g/moli
m= 2000moli . 56g/moli= 112000g= 112kg CaO
c.
15 mmoli NaNO2--------> 0,015moli
M= 23 + 14 + 2.16=69--------> 69g/moli
m= 0,015moli . 69g/moli= 1,035 g NaNO2
a.
272 g H2 S
M= 2 + 32= 34---> 34g/moli
n= m : M
n= 272g : 34g/moli= 8moli H2 S
1mol H2 S----------6,023.10²³ molecule H2S
8 moli---------------------------x
x= 8 . 6,023.10²³=48,184 .10²³ molecule H2S
b.
10,2 kg NH3-----> 10200g
M= 14 + 3=17----> 17g/moli
n= 10200g : 17g/moli=17 moli NH3
1mol NH3-------------6,0223.10²³molecule NH3
17moli-------------------------x
x= 17 . 6,0232.10²³ = 102,391 .10²³molecule NH3
d.
100mL C3H6O
m= q . V
m= 0,8g/mL . 100mL= 80 g C3H6O
M = 3 . 12 + 6 + 16= 58 ----> 58 g/moli
n= 80g : 58 g/moli = 1,38 moli C3H6O
1mol C3H6O----------6,023.10²³ molecule C3H6 O
1,38 moli-----------------------------x
x= 1,38 . 6,023.10 ²³ molecule =