Question

calculeaza masa de magneziu de puritate 90% care reactioneaza cu apa pt a obtine 3 moli de hidroxid de magneziu

Answer 1

Răspuns:

MMg(OH)2=24+2×16+2×1=58g/mol

n=m/M

m=3x58=174gMg(OH)2

MMg=24g/mol

24g.........................58g

Mg + 2H2O => Mg(OH)2 + H2

xg.............................174g

x= 174x24/58=72gMg

100g Mg.............90gMg pur

72gMg...................ygMg pur

y=72×90/100=64,8g Mg pur.