Question

Calculeaza numarul de moli corespunzatori urmatoarelor cantitati de substante:

a) 18,9g acid azotic

b) 14,8g hidroxid de calciu

c) 0,42kg N2

d) 0,147kg H2SO4

e) 48,6g H2O

f) 192g O2

Answer 1

Răspuns:

a)

MHNO3=1+14+3×16=63g/mol

n=m/M=18,9/63= calculeaza

b)

MaCa(OH)2=40+2×16+2×1=74g/mol

n=m/M=14,8/74= calculeaza

c)

MN2=2×14=28g/mol

n=m/M=0,42/28= calculeaza

d)

MH2SO4=2×1+32+4×16=98g/mol

n=m/M=0,147/98= calculeaza

e)

MH2O=2×1+16=18 g/mol

n=m/M=48,6/18= calculeaza

f)

MO2=2×16=32g/mol

n=m/M=192/32= calculeaza

Explicație: