Question

Calculeaza:
x=[(2^3)^5:4^6-3•(2^3+3-3^2)]•(2^2)^3
Vă rog ajutațimă

Answer 1

x=[(2^3)^5:4^6-3•(2^3+3-3^2)]•(2^2)^3

x = [2^15:2^12 -3×(8+3-9)]×2^6

x = (2^3 - 3 × 2) × 2^6

x = (8 - 6) × 2^6

x = 2 × 2^6

x = 2^7

x = 128