Question

calculeazaD2^n intersectat cu D2n+1 unde n apartine N

Answer 1

[tex]\it D_{2^n} = \{1, \ 2, \ 2^2, \ 2^3, ...,\ 2^n\} \\ \\ D_{2^{n+1}} = \{1, \ 2, \ 2^2, \ 2^3, ...,\ 2^n,\ 2^{n+1}\} \\ \\ D_{2^n} \cap D_{2^{n+1}} = D_{2^n} [/tex]