Question

Care este randamentul reactiei de mai jos daca se considera ca 4.00 grame de C2H6 reactioneaza si se formeaza 5.76 grame de CO2. 
 
2 C2H6(g) + 7 O2(g) → 4 CO2(g) + 6 H2O(g)

Answer 1

teoretic : ntCO2 = 2nC2H6 = 2·4/30 = 4/15 moli
practic : np = 5,76/44 = 1,44/11 moli
η = 1,44/11 ·15/4 ·100 = 49,09%