Question

Care este randamentul unui motor termic daca prin arderea a 10 kg de benzina se obtine un lucru mecanic de 114950 kJ ? ( q=45,98 Mj/kg)

Answer 1

η=$\frac{L}{Q}$
q=$\frac{Q}{m}$
q=45.98 MJ=45980kJ
Q=m*q=10*45980=459800kJ
η=$\frac{114950}{45980}$=0,25=25%
η=25%