Question

Care este rezultatul acestui exercitiu Log3 (6x+5)=2

Answer 1

Conditii de existenta: 6x+5 > 0 => x ∈ (-5/6, +∞)

log₃(6x+5) = log₃(3²) => 6x+5 = 9 => 6x = 4 => x =2/3 ∈ D (domeniului de definitie)

S = {2/3}

Answer 2

[tex] log_{3}(6x+5)=2 \\ DVA :6x+5\ \textgreater \ 0 \\ 6x+5=3^2 \\ 6x+5=9 \\ 6x=9-5 \\ 6x=4 \\ x= \frac{4}{6} \\ x= \frac{2}{3} [/tex]
S={2/3}