Question

Care ma poate ajuta?? Va rog mult​

Answer 1

Răspuns:

x²+3x+2=x²+2x+1+x+1=(x+1)²+(x+1)=(x+1)(x+1+1)=(x+1)(x+2)

x²+4x+4=(x+2)²

x²-4=(x+2)(x-2)

E(x)=[1/(x+2)+(x+1)(x+2)/(x+2)²-x/((x-2)]:(x+2)/(x+2)(x-2)

E(x)= [1/(x+2)+((x+1)/(x+2)-x/(x-2)]:1/(x-2)

E(x)= [(1+x+1)/(x+2)-x/(x-2)]·(x-2)

E(x)= [(x+2)/(x+2))-x/(x-2)] · (x-2)

E(x)= [1-x/(x-2)] · (x-2)

E(x)= (x-2)-x=x-2-x

E(x)= -2

Explicație pas cu pas: