Question

Care numere naturale consecutive au produsul egal cu 132?

Answer 1

x(x+1)=132
$x^{2}$ +x=132
$x^{2}$ +x-132=0
Δ=$1^{2}$-4·1·(-132)=529
$x_{1}$= $\frac{-1+ \sqrt{529} }{2 }$=$\frac{-1+23}{2}$=$\frac{22}{2}$=11
$x_{2}$ este negativ
deci numerele sunt 11 si 12