Question

Care sunt formulele de calcul prescurtate?

Answer 1

Explicație pas cu pas:

$(x + y)^{2} = {x}^{2} + 2xy + {y}^{2}$

$(x - y)^{2} = {x}^{2} - 2xy + {y}^{2}$

${x}^{2} - {y}^{2} = (x + y)(x - y)$

${(x + y)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y)$

${(x - y)}^{3} = {x}^{3} - {y}^{3}- 3xy(x - y)$

${x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

${x}^{3}-{y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} )$

$(x + y + z)^{2} = {x}^{2} +{y}^{2} + {z}^{2} + 2(xy + yz + xz)$