Question

cat fac : [27*25-63*2*3+(426:3+4*p):2]:4*6=714

Answer 1

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Answer 2

$\frac{\left(27\cdot \:25-63\cdot \:2\cdot \:3+\frac{\left(\frac{426}{3}+4p\right)}{2}\right)}{4}\cdot \:6=714 \\ \\ \frac{27\cdot \:25-63\cdot \:2\cdot \:3+\frac{\frac{426}{3}+4p}{2}}{4} \\ \\ \\ =\frac{\frac{4p+\frac{426}{3}}{2}+297}{4}=\frac{2p+71+297}{4}=\frac{2p+368}{4}=\frac{2\left(p+184\right)}{4}=\frac{p+184}{2} \\ \\ \\ \frac{\left(p+184\right)\cdot \:6}{2}=714 \\ \\ \\ 3\left(p+184\right)=714 \\ \\ \\ p+184=238 \\ \\ \\ p=54$