Question

Cat face dar spunetiimi

Answer 1

$\left \{ {{x+y=10} \atop {x-y=2}} \right. \to \left \{ {{x=10} \atop {x=2}}+ \right. \to 2x=12 \to x= \frac{12}{2} \to x=6 \\ \left \{ {{x=6 \text{ } \text{ } \text{ }} \atop {6+y=10}} \right. \to \left \{ {{x=6_\text{ } \text{ }} \atop {y=10-6}} \right. \to \left \{ {{x=6} \atop {y=4}} \right. \to S=(6;4) \\ \text{Aplicam metoda reducerii si anulam igrecii}$

Answer 2

x-y=2 (1)
x+y=10 (2)
 Din 1 iese ca x=2+y, inlocuim in 2 si reiese ca 2+y+y=10, scadem 2
si avem ca 2y=8 (impartim cu 2)=> y=4 iar x=2+y => x=2+4=6

Sper ca te-am ajutat