Question

Cate numere impartite la 9 dau catul 6 ? 

Answer 1

[tex]d:9=6+r \\ r<9 \\ r=\{0,1,2,3,4,5,6,7,8\} \\ d=\{9*6+0,9*6+1,9*6+2,9*6+3,9*6+4,......9*6+8\} \\ d=\{54,55,56,57,58,59,60,61,62\} \\ In~total~9~numere.[/tex]

Answer 2

x:9=6 rest
x=6x9+rest
r<9
r=0,1,2,3,4,5,6,7,8
r=0,x=6x9+0=54
r=1,x=54+1=55
r=2,x=54+2=56
r=3,x=54+3=57
r=4,x=54+4=58
r=5,x=54+5=59
r=6,x=54+6=60
r=7,x=54+7=61
r=8,x=54+8=62
x=54,55,56,57,58,59,60,61,62-sunt 9 numere