Question

Cate submulțimi cu 3 elemente are multimea {0,1,2...,10 }

Answer 1

$C_{11}^{3}=\frac{11!}{3!\cdot (11-3)!}=\frac{8!\cdot 9\cdot 10\cdot 11}{3!\cdot 8!}= 165$

Answer 2

Răspuns:

165

Explicație pas cu pas:

Combinari de 11 luate cate 3 = 11! / (3! * (11-3)!) = 11! /(3! * 8!) = 9*10*11 / 2*3 =

3 * 5 * 11 = 165