Question

ce cantitate de NaOH neutralizeaza 1 mol de HCL?

Answer 1

NaOH + HCl = NaCl + HOH
$M_{NaOH}$ = 23+16+1= 40 g/mol 
$M_{HCl}$ = 1+35,5=36,5 g/mol
n=$\frac{m}{M}$ => m=1*36,5=36,5 g HCl
$\frac{x}{40}$=$\frac{36,5}{36,5}$ => x=$\frac{36,5*40}{36,5}$ 
=> x=40 g NaOH