Question

ce cantitate de Zn si HCl se consuma pentru a obtine 4g hidrogen?
e urgent

Answer 1

Zn+ 2HCl= ZnCl2+H2

n=m/M= 4/2= 2 moli H2 M H2=2

din ec.r.ch observăm:

1 mol Zn/ x= 1 mol H2/2 moli H2

x= 2 Moli Zn. m= nxA= 2x 65= 130g Zn

2 mol HCl/ y= 1 molH2/2moliH2

y=4 moli HCl. M HCl= 36.5. m= nxM= 4x 36.5=146 g HCl