Question

ce fel de fracție este b) 1²⁰¹⁹supra 2018⁰ c)(2⁴)³supra(3²)⁶​

Answer 1

$\it \dfrac{1^{2019}}{2018^0}=\dfrac{1}{1}=1 \Rightarrow \ frac\c{\it t}ia\ este\ echiunitar\breve a\\ \\ \\ \dfrac{(2^4)^3}{(3^2)^6}=\dfrac{2^{4\cdot3}}{3^{2\cdot6}}=\dfrac{2^{12}}{3^{12}}=\bigg(\dfrac{2}{3}\bigg)^{12};\ \ \ \dfrac{2}{3} < 1 \Rightarrow \bigg(\dfrac{2}{3}\bigg)^{12} < 1\ (subunitar\breve a)$