Question

Ce volum de benzen (cu densitatea de 0,88 g/cm^3) si de etena , sunt necesare pentru a se obtine 1060 Kg de etilbenzen , randamentul reactiei fiind de 50% ?

Answer 1

C6H6 + CH2=CH2 => C6H5-CH2-CH3

0,5*1060=530kg 

78kg C6H6.................28kg C2H4...............106kg C8H10

x kg.............................ykg............................530kg

x=390kg=390000g C6H6

y=140kg=140000g C2H4

ro=ms/V => V=ms/ro=390000/0,88=443,181818 L = 0,443m3 C6H6

ro=ms/V=>V=140000/0,88=159,09L C2H4