Question

ce volum de gaze se degaja la explozia unui kilogram de trinitrat de glicerina la temperatura 3000C?

Answer 1

MC3H5(ONO2)3=3AC+5AH+3(AO+AN+2AO)=3*12+5*1+3(16+14+2*16)=227g/mol

1kg=1000g

n=m/M=1000/227=4.4 moli trinitrat 

4moli............................12+10+6+1=29 moli
4C3H5(ONO2)3 → 12CO2 + 10H2O + 6N2 + O2
4.4 moli............................x=31.9 moli gaze

T=273+T°C = 273 + 3000 = 3273K

pV=nRT==>V=nRT/p=31.9*0.082*3273/1=8561.5135L gaze