Question

Ce volum ocupa in conditii normale :
a) 6,023 * 10^28 molecule Cl2
b) 12,046 * 10^25 molecule Nh3

Answer 1

SE UTILIZEAZA relatiile cu care se calculeaza numarul de moli

niu=V/Vm      si   niu=N/N,A----------> V/Vm=N/N,A-->V=NxVm/N,A

N,A= 6,023X10²³ molec/mol ,    numarul lui Avogadro

a) V=6,023X10²⁸x22,4/6,023X10²³ L=22,4X10⁵L

b) 12,046x10²⁵x22,4/ 6,023x10²³ l=200x22,4 l= 4480 l

Answer 2

a) 1molCl2............6.023×10^23moleculeCl2

X..........................6.023×10^28molec Cl2

X=6.023×10^28/6.023×10^23=1×10^5= 100000moli

1mol..............22.4l

100000........y

y=22.4×10^5 l

b) 1molNH3..........6.023×10^23molec NH3

X..............12.046×10^25molec NH3

x=12.046×10^25/6.023×10^23=2×10^2=200 moli

1moli...........22.4l

200moli.....y

y=22.4×200=4480l