Question

cerinta:bagati 5 in radical din 6,7 in 6,4in5,-11 in 6,-5 in 3 si -7 pe 2 in 2
repede plssss

Answer 1

Explicație pas cu pas:

$5 \sqrt{6} = \sqrt{ {5}^{2} \cdot 6} = \sqrt{25 \cdot 6} = \sqrt{150}$

$7 \sqrt{6} = \sqrt{ {7}^{2} \cdot 6} = \sqrt{49 \cdot 6} = \sqrt{294}$

$4 \sqrt{5} = \sqrt{ {4}^{2} \cdot 5} = \sqrt{16 \cdot 5} = \sqrt{80}$

$- 11 \sqrt{6} = - \sqrt{ {11}^{2} \cdot 6} = - \sqrt{121 \cdot 6} = - \sqrt{726}$

$- 5 \sqrt{3} = - \sqrt{ {5}^{2} \cdot 3} = - \sqrt{25 \cdot 3} = - \sqrt{75}$

$- \dfrac{7}{2} \sqrt{2} = - \sqrt{ \dfrac{ {7}^{2}}{ {2}^{2} } \cdot 2} = - \sqrt{\dfrac{49}{2}}$