Question

Cine am ajuta si pe mine la matematică

Answer 1

$\frac{1}{2} = {2}^{ - 1} \\ \\ \frac{4}{3} = {( \frac{3}{4}) }^{ - 1} \\ \\ 5 = {( \frac{1}{5}) }^{ - 1} \\ \\ ( \frac{2}{3} )^{2} = {( \frac{3}{2}) }^{ - 2} \\ \\ {( - \sqrt{3}) }^{4} = {( - \frac{1}{ \sqrt{3} }) }^{ - 4} \\ \\ ( { \frac{1}{ \sqrt{3} } )}^{6} = { \sqrt{ 3} }^{ - 6}$