Question

Cine imi rezolva asta are coroanaa :o

Answer 1

$a)x\sqrt{2}+x\sqrt{8}+x\sqrt{32}=\sqrt{4}+\sqrt{16}+\sqrt{64} =\ \textgreater \ \\ =\ \textgreater \ x\sqrt{2} + x * 2\sqrt{2}+ x * 4\sqrt{2} = 2 + 4 + 8 =\ \textgreater \ \\ =\ \textgreater \ x\sqrt{2}+2x\sqrt{2}+4x\sqrt{2}=14 =\ \textgreater \ (x+2x+x)\sqrt{2}=14 =\ \textgreater \ \\ =\ \textgreater \ 4x = \frac{14}{\sqrt{2}} =\ \textgreater \ x = \frac{14\sqrt{2}}{4*2}} =\ \textgreater \ x = \frac{7\sqrt{2}}{4} \\ b) \sqrt{5}(x+4)+2\sqrt{5}(x-2)=\sqrt{15} =\ \textgreater \ \\ =\ \textgreater \ \sqrt{5}x+4\sqrt{5}+2\sqrt{5}x-4\sqrt{5}=\sqrt{15} =\ \textgreater \ 3\sqrt{5} x = \sqrt{15} =\ \textgreater \ \\ x= \frac{\sqrt{15}}{3\sqrt{5}} =\ \textgreater \ x = \frac{\sqrt{3}}{3}$