Question

Cine ma ajuta dau coroană, plss​

Answer 1

$\it a)\ \ x\ne0,\ \ a\ne0\\ \\ \dfrac{a^3x}{3}\cdot\dfrac{2a^2}{24x}=\dfrac{a^3x}{3}\cdot\dfrac{24x}{2a^2} = 4ax^2\\ \\ \\ b)\ \ x\in\mathbb{R}\\ \\ \dfrac{12x^2}{4}:2x^2=3x^2:2x^2=3\cdot\dfrac{x^2}{2}\cdot x^2=\dfrac{3x^4}{2}$