Question

Cine ma ajuta la subiectul II

Answer 1

1.
a) √36/√(6²+8²)=√36/√(36+64)=√36/√100=6/10=3/5

b) 5√162+10√12-6√75-3√50=45√2+20√3-30√3-15√2=30√2-10√3=
=10(3√2-√3)

c) 3×I√5-√3I-I3√5-4√3I=3×(√5-√3)-(4√3-3√5)=3√5-3√3-4√3+3√5=
=6√5-7√3
√5-√3>0        I√5-√3I=√5-√3
3√5-4√3<0    I3√5-4√3I=-(3√5-4√3)=4√3-3√5

d) (-2)³- 2 2/3:(-8/9)-(-1/2)³+(-5 2/5):3/10=
=-8- 8/3 ×(-9/8)+1/8+(-27/5)×10/3=
=-8+3+1/8+(-18)=
=-5+1/8-18=
=-23+1/8=(-184+1)/8=-183/8

1 2/5 ×(x-3)- 2 1/3 = 4/5 × (x-1)-x
7/5 ×(x-3)- 7/3 = 4/5 × (x-1)-x
21(x-3)-35=12(x-1)-15x
21x-63-35=12x-12-15x
21x-98=-12-3x
24x=-12-28
24x=-40
x=40/28=10/7