Question

Cine ma ajuta si pe mine?

Poze mai jos

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V

Answer 1

c) $\frac{1}{2} + \frac{5}{6} * \frac{1}{25} - \frac{15-1}{90}$
$\frac{1}{2} + \frac{5}{6*25} - \frac{14}{90} =\ \textgreater \ \frac{1}{2} + \frac{5}{150} - \frac{14}{90}$
(vom aplifica pe $\frac{1}{2}$ cu 225, pe $\frac{5}{150}$ cu 3 iar pe $\frac{14}{90}$ cu 4 pentru a le aduce la acelasi numitor(450)
$=\ \textgreater \ \frac{225}{450} + \frac{15}{450} - \frac{56}{450} = \frac{184}{450}$
Vom simplifica cu 2: $= \frac{92}{225}$

d)$\frac{3}{9} : \frac{6}{10} +( \frac{1}{4} - \frac{5}{10} ) ^{2}$
$\frac{3}{9} * \frac{10}{6} + (\frac{10}{40} + \frac{20}{40})^2$